4x/x^2+4x-32

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Solution for 4x/x^2+4x-32 equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4*x+(4*x)/(x^2)-32 = 0

4*x^1+4*x^-1-32*x^0 = 0

(4*x^2-32*x^1+4*x^0)/(x^1) = 0 // * x^2

x^1*(4*x^2-32*x^1+4*x^0) = 0

x^1

4*x^2-32*x+4 = 0

4*x^2-32*x+4 = 0

DELTA = (-32)^2-(4*4*4)

DELTA = 960

DELTA > 0

x = (960^(1/2)+32)/(2*4) or x = (32-960^(1/2))/(2*4)

x = (8*15^(1/2)+32)/8 or x = (32-8*15^(1/2))/8

x in { (32-8*15^(1/2))/8, (8*15^(1/2)+32)/8}

x in { (32-8*15^(1/2))/8, (8*15^(1/2)+32)/8 }

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